参数
1 | public ThreadPoolExecutor( |
workCount 记录了运行中的线程数
- 如果workerCount < corePoolSize,则创建并启动一个线程来执行新提交的任务。
- 如果workerCount >= corePoolSize,且线程池内的阻塞队列未满,则将任务添加到该阻塞队列中。
- 如果workerCount >= corePoolSize && workerCount < maximumPoolSize,且线程池内的阻塞队列已满,则创建并启动一个线程来执行新提交的任务。
- 如果workerCount >= maximumPoolSize,并且线程池内的阻塞队列已满, 则根据拒绝策略来处理该任务, 默认的处理方式是直接抛异常。
常见线程池
Executors.newFixedThreadPool(int)
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5public static ExecutorService newFixedThreadPool(int nThreads) {
return new ThreadPoolExecutor(nThreads, nThreads,
0L, TimeUnit.MILLISECONDS,
new LinkedBlockingQueue<Runnable>());
}Executors.newCachedThreadPool()
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5public static ExecutorService newCachedThreadPool() {
return new ThreadPoolExecutor(0, Integer.MAX_VALUE,
60L, TimeUnit.SECONDS,
new SynchronousQueue<Runnable>());
}
这类线程池比较适合执行大量的耗时较少的任务。当整个线程池都处于闲置状态时,线程池中的线程都会超时而被停止这个时候CachethreadPool之中实际上是没有任何线程的。它几乎不占任何系统资源。
- Executors.newScheduledThreadPool(int corePoolSize)
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7public static ScheduledExecutorService newScheduledThreadPool(int corePoolSize) {
return new ScheduledThreadPoolExecutor(corePoolSize);
}
public ScheduledThreadPoolExecutor(int corePoolSize) {
super(corePoolSize, Integer.MAX_VALUE, 0, NANOSECONDS, new DelayedWorkQueue());
}
他的核心线程数量是固定的,而非核心线程数是没有限制的,并且当非核心线程闲置时会被立即回收,ScheduledThreadPool这类线程池主要用于执行定时任务和具有固定周期的重复任务。
- Executors.newSingleThreadExecutor()
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6public static ExecutorService newSingleThreadExecutor() {
return new FinalizableDelegatedExecutorService
(new ThreadPoolExecutor(1, 1,
0L, TimeUnit.MILLISECONDS,
new LinkedBlockingQueue<Runnable>()));
}
任务的提交
1 | public void execute(Runnable command) { |
尝试创建新线程1
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55private boolean addWorker(Runnable firstTask, boolean core) {
retry:
for (;;) { // 检查是否超出最大数量限制,超出直接return false
...
for (;;) {
int wc = workerCountOf(c);
if (wc >= CAPACITY ||
wc >= (core ? corePoolSize : maximumPoolSize))
return false;
if (compareAndIncrementWorkerCount(c))
break retry;
c = ctl.get(); // Re-read ctl
if (runStateOf(c) != rs)
continue retry;
// else CAS failed due to workerCount change; retry inner loop
}
}
boolean workerStarted = false;
boolean workerAdded = false;
Worker w = null;
try {
w = new Worker(firstTask);
final Thread t = w.thread;
if (t != null) {
final ReentrantLock mainLock = this.mainLock;
mainLock.lock();
try {
int rs = runStateOf(ctl.get());
if (rs < SHUTDOWN ||
(rs == SHUTDOWN && firstTask == null)) {
if (t.isAlive()) // precheck that t is startable
throw new IllegalThreadStateException();
workers.add(w);
int s = workers.size();
if (s > largestPoolSize)
largestPoolSize = s;
workerAdded = true;
}
} finally {
mainLock.unlock();
}
if (workerAdded) {
t.start(); // 启动线程
workerStarted = true;
}
}
} finally {
if (! workerStarted)
addWorkerFailed(w);
}
return workerStarted;
}
Worker.run1
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71 public void run() {
runWorker(this);
}
final void runWorker(Worker w) {
Thread wt = Thread.currentThread();
Runnable task = w.firstTask;
w.firstTask = null;
w.unlock(); // allow interrupts
boolean completedAbruptly = true;
try {
// 这是一个循环,防止线程退出,多个task复用线程
while (task != null || (task = getTask()) != null) { // 执行firTask或者从 阻塞队列中获取task
w.lock();
...
try {
beforeExecute(wt, task);
try {
task.run();
} finally {
afterExecute(task, thrown);
}
} finally {
task = null;
w.completedTasks++;
w.unlock();
}
}
completedAbruptly = false;
} finally {
processWorkerExit(w, completedAbruptly);
}
}
private Runnable getTask() {
boolean timedOut = false; // Did the last poll() time out?
for (;;) {
int c = ctl.get();
int rs = runStateOf(c);
// Check if queue empty only if necessary.
if (rs >= SHUTDOWN && (rs >= STOP || workQueue.isEmpty())) {
decrementWorkerCount();
return null;
}
int wc = workerCountOf(c);
// 是否执行超时检查
boolean timed = allowCoreThreadTimeOut || wc > corePoolSize;
if ((wc > maximumPoolSize || (timed && timedOut))
&& (wc > 1 || workQueue.isEmpty())) {
if (compareAndDecrementWorkerCount(c))
return null;
continue;
}
try {
Runnable r = timed ?
workQueue.poll(keepAliveTime, TimeUnit.NANOSECONDS) : // 尝试从阻塞队列中获取任务,超时时间为 keepAliveTime
workQueue.take(); // 直接获取task
if (r != null)
return r;
timedOut = true;
} catch (InterruptedException retry) {
timedOut = false;
}
}
}